Moderate Difficulty
Create a method that offsets each letter in a
String by one to the right. See the example code below. To get a perfect on this you must research and take advantage of the
String classes's .
toCharArray() method. This method creates an array of
chars (char[]) from a string. It's probably easier to do this with a loop and making use of
String class's .substring() method.
//@returns a string whose characters have been increased by one and
//bump last letter to front
//example input and output
// input output
//abc cab
//abcdef fabcde
public String offsetByOne (String str)
Make the program below function
//@returns true if parameter is a palindrome;
boolean isPalindrome(String potentialPalindrome(){
return false;
}
The right is a screen shot of this project. Your job is to validate that the user has entered his or her information. (ValidateForm Source Code )
- Make a helper method called
isAllAlpha(String str). This method should return true if every character in str is a letter, upper or lower case.
Make 1 master String that has the alphabet "abcdefghijklmnopqrstuvABCDEFGHIJKLMNOPQRSTUV" and check each character in the str against that master String
- Make a helper method called
isNumeric(String str). This method should return true if every character in str is a number. In addition, can contain, at most, 1 '.'
- Make sure that the name is at least 2 letters and includes no numbers
- Make sure that the password is at least 4 characters, contains at least 1 number, 1 lower case letter and 1 upper case letter.. Also, don't let the user's password be the same as his or her name
- the email must include an @ as well as a "." and the "." must come after the "@"
- the zip code must be all numbers and be the right length (zip codes have between 3 and 5 digits)
- make sure that the person was born at reasonable date (not 1820 or this year!)
- ensure that the phone number is valid (no letters and follows the prescribed format)
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